Inspect
Review the problem, diagram, and evidence.
The refrigerator removed 6 kW of heat using 2 kW of work. A COP of 3 was correct, not impossible.
Inspect, commit, prove, fix, and sign off.
Follow the investigation process used in the field β in five guided steps.
Review the problem, diagram, and evidence.
Choose your hypothesis.
Run calculations and test your idea.
Select and validate a safe correction.
See the full debrief and key takeaways.
A refrigerator removes 6 kW of heat from a cold space while consuming 2 kW of electrical work. A reviewer rejects the calculated COP of 3 because it exceeds 1. Determine the correct COP and condenser heat rejection, then explain why the result does not violate the first law.
Find the root cause, confirm the fix, and see how this connects to the exam.
COP was interpreted as if it were a thermal efficiency.
The refrigerator moves heat in addition to consuming work.
Use COP_R=QL/W and QH=QL+W.
Refrigerator COP is QL/W. Removing 6 kW with 2 kW of work gives COP_R=3. The condenser rejects QH=QL+W=8 kW, so energy is conserved even though COP exceeds 1.
Refrigerator COP measures heat moved per unit work input, not the fraction of input energy converted to useful output. COP_R can exceed 1.
Yes. COP measures heat moved per unit work input, not conversion efficiency.
QH=8 kW.
Each case is designed to build the judgment, analysis, and confidence you need for engineering exams β and beyond.
Basic subject familiarity helps, but every case is designed to teach through the investigation itself.
Most cases are designed for a focused 5β10 minute investigation.
Each case is mapped to a verified exam, subject, topic, and misconception before publication.
The sealed debrief unlocks with the root cause, corrected reasoning, fix, and takeaway.