Inspect
Review the problem, diagram, and evidence.
The total load was 28 kN, but the support reactions were not 14 kN each.
Inspect, commit, prove, fix, and sign off.
Follow the investigation process used in the field β in five guided steps.
Review the problem, diagram, and evidence.
Choose your hypothesis.
Run calculations and test your idea.
Select and validate a safe correction.
See the full debrief and key takeaways.
A simply supported 6 m beam has a pin at A and a roller at B. An 8 kN downward load acts 1 m from A, and a 20 kN downward load acts 4 m from A. A quick check assigns 14 kN to each support because the total load is 28 kN. Calculate the actual reactions and identify why the equal split is incorrect.
Find the root cause, confirm the fix, and see how this connects to the exam.
The reaction split was based only on total force.
The loads create unequal moments about the supports.
Use Ξ£F=0 and Ξ£M=0 on the complete beam free-body diagram.
For a 6 m simply supported beam with 8 kN at 1 m and 20 kN at 4 m from A, moment equilibrium about A gives RB(6)=8(1)+20(4)=88, so RBβ14.67 kN. Vertical equilibrium then gives RAβ13.33 kN.
Use both force equilibrium and moment equilibrium. Load location controls the reaction distribution.
No. Equal reactions occur only for appropriate symmetric loading.
It removes that support reaction from the moment equation and lets the other reaction be solved directly.
Each case is designed to build the judgment, analysis, and confidence you need for engineering exams β and beyond.
Basic subject familiarity helps, but every case is designed to teach through the investigation itself.
Most cases are designed for a focused 5β10 minute investigation.
Each case is mapped to a verified exam, subject, topic, and misconception before publication.
The sealed debrief unlocks with the root cause, corrected reasoning, fix, and takeaway.