FE Mechanical Practice Question Solution included after investigation
CASE E-051 Β· FE

The Sealed Tank That Reached 150 kPa, Not 133

The gas temperature rose from 300 K to 450 K. The pressure did not scale with Celsius temperature.

β–Ά INTERACTIVE CASE FILE β€’ 5–10 MIN β€’ CLICK TO INVESTIGATE

Inspect, commit, prove, fix, and sign off.

Case E-051 engineering failure visual
HOW THIS WORKS

Think like
a real engineer.

Follow the investigation process used in the field β€” in five guided steps.

1

Inspect

Review the problem, diagram, and evidence.

2

Commit

Choose your hypothesis.

3

Prove

Run calculations and test your idea.

4

Fix

Select and validate a safe correction.

5

Sign Off

See the full debrief and key takeaways.

Case Brief

SAME PRINCIPLES. HIGHER STANDARDS.
PROBLEM STATEMENT

A sealed rigid tank contains an ideal gas initially at 100 kPa and 300 K. The tank is heated until the gas reaches 450 K. A calculation using Celsius temperatures predicts the wrong final pressure. Determine the correct final pressure and identify why absolute temperature is required.

Thermodynamics Mechanical Design Verification Root Cause Analysis Safe Correction
E-051
INVESTIGATION WORKSPACE WORK THROUGH THE CASE β€” YOUR CHOICES MATTER.
πŸ”’
DEBRIEF (LOCKED)

Complete the investigation
to unlock the full debrief.

Find the root cause, confirm the fix, and see how this connects to the exam.

πŸ”’Root causeComplete the case
to reveal
πŸ”’Correct fixComplete the case
to reveal
πŸ”’Exam takeawayComplete the case
to reveal
CASE CLOSED Β· ENGINEERING VERDICT

What actually failed β€” and what should change.

What failed

A temperature ratio was formed using a nonabsolute scale.

What was missed

Thermodynamic zero matters in gas-law ratios.

Corrected model

Use P/T=constant at fixed mass and volume, with T in Kelvin or Rankine.

QUICK ANSWER

For a fixed mass of ideal gas in a rigid tank, P/T is constant when temperature is absolute. Starting at 100 kPa and 300 K, heating to 450 K gives P2=100(450/300)=150 kPa.

ENGINEERING TAKEAWAY

For a fixed mass of ideal gas in a rigid tank, P1/T1=P2/T2 with T in Kelvin or Rankine.

CASE QUESTIONS

Questions this case should settle.

Why must Kelvin be used in ideal-gas temperature ratios?

Because gas-law proportionalities require absolute thermodynamic temperature.

What happens to ideal-gas pressure in a rigid tank when absolute temperature rises 50%?

Pressure also rises 50%, assuming fixed mass and ideal-gas behavior.

NEXT FE PRACTICE QUESTION

The Refrigerator With a COP Greater Than One

Thermodynamics Β· 5–10 min

Continue Practice β†’
WHAT YOU’LL LEARN

Real failures. Lasting skills.

Each case is designed to build the judgment, analysis, and confidence you need for engineering exams β€” and beyond.

  • Apply core engineering concepts to real-world problems
  • Practice structured troubleshooting and analysis
  • Strengthen exam-ready thinking through realistic scenarios
COMMON QUESTIONS
Do I need prior knowledge to use these cases?

Basic subject familiarity helps, but every case is designed to teach through the investigation itself.

How long does a case take?

Most cases are designed for a focused 5–10 minute investigation.

Are the cases aligned with engineering exams?

Each case is mapped to a verified exam, subject, topic, and misconception before publication.

What happens after I complete a case?

The sealed debrief unlocks with the root cause, corrected reasoning, fix, and takeaway.