Inspect
Review the problem, diagram, and evidence.
The resistivity formula was correct, but 2 mm² was treated as 2×10^-9 m² instead of 2×10^-6 m². The wire resistance was 0.17 ohm.
Inspect, commit, prove, fix, and sign off.
Follow the investigation process used in the field — in five guided steps.
Review the problem, diagram, and evidence.
Choose your hypothesis.
Run calculations and test your idea.
Select and validate a safe correction.
See the full debrief and key takeaways.
A 20 m conductor has resistivity rho=1.7×10^-8 ohm·m and cross-sectional area 2.0 mm². A note converts the area to 2×10^-9 m² and reports 170 ohm. Determine the correct resistance, voltage drop at 10 A, and conductor power loss.
Find the root cause, confirm the fix, and see how this connects to the exam.
The area unit was converted as a linear dimension.
1 mm²=10^-6 m².
Convert area correctly, then use R=rho L/A.
2 mm²=2×10^-6 m². Therefore R=(1.7×10^-8)(20)/(2×10^-6)=0.17 ohm. At 10 A, voltage drop is 1.7 V and power loss is 17 W.
Convert squared length units correctly, then use R=rho L/A.
1×10^-6 m².
Each case is designed to build the judgment, analysis, and confidence you need for engineering exams — and beyond.
Basic subject familiarity helps, but every case is designed to teach through the investigation itself.
Most cases are designed for a focused 5–10 minute investigation.
Each case is mapped to a verified exam, subject, topic, and misconception before publication.
The sealed debrief unlocks with the root cause, corrected reasoning, fix, and takeaway.